ostriches are quasmatic
by kade and jd July 3, 2009
Get the quasmatic mug.The Schrödinger's Cat of equations. Nobody really knows what it is or what it means. The easiest way to commit an algebraic atrocity.
What the hell is a quasi quadratic?
by It'sMillerTime October 23, 2018
Get the quasi quadratic mug.x = -b plus or minus the square root of (b^2 - 4ac) all divided by 2a. Used for quadratic equations where you can't factor. the equation is ax^2 + bx + c.
by Yo fucking momma December 17, 2003
Get the quadratic formula mug.The best method of solving a quadratic. When your equation is in the standard form of ax² + bx + c = 0, x = (-b ± √b² - 4ac) / 2a. It is far superior to both factoring and completing the square. The equation may look difficult, but all you have to do is plug in the coefficients and simplify!
A: I had to use the quadratic formula to solve that tricky problem.
B: Why didn't you just do that in the first place?
B: Why didn't you just do that in the first place?
by WeWillAllDieSoon November 11, 2020
Get the Quadratic Formula mug.Simply the most useless maths topic ever. i dont think ill ever be at the shops, looking to buy $2 of bananas and for some reason need to calculate where the bloody parabola is meant to go on the x and y axis. useless. id rather stick my nuts under
Teacher: Okay guys, time to continue on with your quadratics work from yesterday.
Me: fuck off u old wrinkly cunt.
Me: fuck off u old wrinkly cunt.
by wont u take me to funkytown March 8, 2009
Get the Quadratics mug.by Rihanyce August 28, 2010
Get the Quadratic peinor mug.A handy formula easily memorized by repetition. It is used in many instances, such as trying to find the roots of an equation, or solving an equation that will not factor with integers.
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
EX:
Hm..
10x^2+13X-5
-13(+,-)sqrt(169+200)/20
>_>
In other words, by substituting the numbers in, you get 13(+,-)sqrt(369)/20.
As you may or may not have guessed, this gives you a very nasty number, which should be approximated and rounded to the nearest thousandth.
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
EX:
Hm..
10x^2+13X-5
-13(+,-)sqrt(169+200)/20
>_>
In other words, by substituting the numbers in, you get 13(+,-)sqrt(369)/20.
As you may or may not have guessed, this gives you a very nasty number, which should be approximated and rounded to the nearest thousandth.
by "Seagaia" May 21, 2005
Get the quadratic formula mug.