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One of the greatest human beings to walk the planet. He plays keyboards and drums for the band Foster the People and is funny and awesome.
“Do you know about Isom Innis from Foster the People?”
“Yes! He is the most awesome pianist for Foster the People!”
“Yes! He is the most awesome pianist for Foster the People!”
by Kiwimaster February 1, 2022
Get the Isom Innis mug.Hym "So, I've read through Isom 1 several times now and I greatly enjoyed it. Interesting and well-drawn characters. Some light power scaling in the form of a couple of fight scenes but both the nature and the depths of Isom's powers remain a mystery (which drives the intrigue). Alludes to some interplanetary and/or supernatural elements. Shows off some of the antagonistic forces we have to look forward to later in the series. The main antagonist likes to monologue and is (therefore) a man after my own heart. There's a lot going on and he leaves a lot of plot threads to be explored in the subsequent issues. After I finished my first read-through I immediately regretted not buying the second book. 10/10 would recommend.
by Hym Iam September 20, 2023
Get the Isom 1 mug.She a beautiful girl. She don't deal with to many people. She a dark skin pretty girl.people always hating on her.Peolple want to be her. Boys want her .....GET YOU A DREKA😍
by Dedrika January 27, 2018
Get the Dedrika Isom mug.Skinner: "Superintendent!.. I was just...stretching my calves on the windowsill! Isometric Exercise! Care to join me?"
by xXGaLaXyXx July 16, 2018
Get the Isometric Exercise mug.Abstract algebra: Take a group G, and a group H, with a group operation *. G is isomorphic to H if there exist a map f: G->H such that:
1: f is injective
2: f is surjective
3: f(a*b)=f(a)*f(b) for all a,b in G
If f satisfies these three properties, f is called an isomorphism.
1: f is injective
2: f is surjective
3: f(a*b)=f(a)*f(b) for all a,b in G
If f satisfies these three properties, f is called an isomorphism.
The map f: Z -> E given by f(a)=2a where Z is the integers and E is the even integers is an isomorphism.
Proof:
Showing injectivity
f(b)=f(a) => 2a=2b (from the given function) <=> a=b
Showing surjectivity
Suppose n is in E. n is an even integer hence n=2k for some integer k.
f(k)=2k=n, hence f is surjective.
Homomorphism:
f(a+b)=2(a+b)=2a+2b=f(a)+f(b)
Hence f is an isomorphism. Q. E. D.
Proof:
Showing injectivity
f(b)=f(a) => 2a=2b (from the given function) <=> a=b
Showing surjectivity
Suppose n is in E. n is an even integer hence n=2k for some integer k.
f(k)=2k=n, hence f is surjective.
Homomorphism:
f(a+b)=2(a+b)=2a+2b=f(a)+f(b)
Hence f is an isomorphism. Q. E. D.
by qsqazxcvfrew March 29, 2018
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