Chain Dog

A term of endearment used between friends that implies the person has been involved in something mischievous.

"Bill, you old chain dog, you! You're at it again!"

by C. Aleccia February 26, 2008

Chainsaw Man Effect

The condition of not being able to fully enjoy most forms of storytelling/media after reading something objectively excellent

Man I just couldn't get through this garbage, it all seems so bleak 'cause of the chainsaw man effect

by Seudori8888 January 9, 2023

gold chainer

A particular class of douchebag who usually wears a gold chain with extra douchosity. A player. Very sleazy sometimes also has a 70's porn moustache. Warning: Even if personality & looks seem ok, a gold chain tells the real story. Steer clear at all costs.

Let's get out of here. There's a gold chainer heading our way.

by samiam11 June 20, 2011

rolex chain

A wide gold chain, but not a herringbone, popular on African American musicians and athletes

That girl was blinging a phat rolex chain at the club!

by KROQKEN November 18, 2011

fly off the chain

to become infuriated, to lose all control of your actions

"Don't f*** with me right now, or I'll fly off the chain."

by .K+. January 10, 2009

cut the chain

the act of a male getting a sex change to become a female.

After he cut the chain Bruse Jenner became Caitlyn Jenner.

by Countyeasy June 5, 2017

chain rule

In calculus, the chain rule is used to differentiate compositions of functions. It states that for any function f which is dependent on a variable u, and u is a function of a second variable x, then f is a function of x.

In Set Theory:

f(u)=u V u(x)=x V Vf(x)

In Calculus:

df/dx = du/dx(dx/du)

to differentiate (x+1)^2, one could multiply this out and apply the sum rule (derivative of a sum is the sum of the derivatives); but what if it were (x+1)^55? Suddenly the multipling out doesn't look so nice. To apply the chain rule, we must first define the functions. Let f(x)=(x+1)^55 and u=(x+1). Therefore f(x)=u^55. By the chain rule:
df/dx = df/du(du/dx)
df/dx = d/du(u^55)(du/dx)
df/dx = 55u(du/dx)
We earlier defined the variable "u" as (x+1). Now we substitute this in.
df/dx = 55(x+1)d/dx(x+1)
df/dx = 55x+55(1)
df/dx = 55x+55

by Gladwarez July 10, 2006