The answer to the simple math problem
floor(abs((sqrt(2)^10 - 32) / (sin(pi/7)^2 + cos(pi/7)^2))) + mod(floor(ln(e^9999)), 3000) - floor(log(10^500)/log(10)) + abs(tan(pi/4)) + 1608*floor((10^6)/(10^6)) + mod(10^6, 999999)
floor(abs((sqrt(2)^10 - 32) / (sin(pi/7)^2 + cos(pi/7)^2))) + mod(floor(ln(e^9999)), 3000) - floor(log(10^500)/log(10)) + abs(tan(pi/4)) + 1608*floor((10^6)/(10^6)) + mod(10^6, 999999)
by anonymous January 6, 2026
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