When in individual becomes so sexually aroused by a mathematical equation that they ejaculate in a parabolic arc.
by Not an Avocado July 01, 2020
by Daddy sqrt November 24, 2019
by PHISH November 25, 2003
Don't try solving it, just put it into google, it makes a nice heart!
idea from some other guy
thanks
idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5
by giant salamanders eat pant May 15, 2020
Don't try to solve it, LOL .
Paste it on Google and a Heart symbol will appear <3
It's a graph drawing from that expression .
Paste it on Google and a Heart symbol will appear <3
It's a graph drawing from that expression .
Hey babe. (sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 !!!
by Nguyen Vu Long December 06, 2011
On May 15, 2020, a user known as "giant salamanders eat paint" said, "Don't try solving it, just put it into google, it makes a nice heart!
idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5" Now this guy forgot to credit the original user who made this. Me. And some dude from 2011 named "Nguyen Vu Long". SO CREDIT US!
idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5" Now this guy forgot to credit the original user who made this. Me. And some dude from 2011 named "Nguyen Vu Long". SO CREDIT US!
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5
Copy-paste it noobs.
Copy-paste it noobs.
by WrySquirrel3069 May 29, 2020