arbitrum

A place where decisions are made.

Truth, justice, lies, criminality, and where their lines are drawn is decided in the arbitrum.

by Zer0 x2f1f June 22, 2023

alpita

A beautiful girl that is sweet as cupcake and would be defined as peanut by the person she is been loved.

He Alpita how you doin!

by Muffinhead2509 June 18, 2021

Permanent Court of Arbitration

(MULTILATERAL GOVERNMENT) International court based in the Hague, the Netherlands; founded in 1889; oldest multilateral court. In some respects, a precursor to the International Court of Justice (also in the Hague--in the same building, the Peace Palace).

The PCA differs from the ICJ in that only national governments may be respondents in the ICJ (which operates like a civil court). The PCA settles disputes that may arise between a private party (such as RCA, in RCA vs. China-1935) and a national government, or between national governments. Parties submit to the PCA when the dispute is a nuisance to both, but relevant laws are uncertain.

The Permanent Court of Arbitration has a three-part organizational structure consisting of an Administrative Council that oversees its policies and budgets, a panel of independent potential arbitrators known as the Members of the Court, and its Secretariat, known as the International Bureau, headed by the Secretary-General.

by Primus Intra Pares July 19, 2010

Arbitration

A day of celebration and feasting on roast beef from Arby's to expand the stomach capacity for Thanksgiving.

Arbitration is a week a way and i am already imagining the beef sweats.

by arbitration movement November 18, 2013

Aritri

If you have an angel, in the form of a friend,that's aritri.
You have everything,if u have an aritri in your life. Smart, beautiful, confident, little shy but, who is not !

Very patient, forgiving sometimes secretive.You can lean on her in your bad times, but make sure you too are there for her when she needs you!!

I am lucky I've got an aritri for life!!

by anonymous July 19, 2021

Fundamental Theorem of Arithmetic

The fundamental theorem of arithmetic states that {n: n is an element of N > 1} (the set of natural numbers, or positive integers, except the number 1) can be represented uniquely apart from rearrangement as the product of one or more prime numbers (a positive integer that's divisible only by 1 and itself). This theorem is also called the unique factorization theorem and is a corollary to Euclid's first theorem, or Euclid's principle, which states that if p is a prime number and p/ab is given (a does not equal 0; b does not equal 0), then p is divisible by a or p is divisible by b.

Proof: First prove that every integer n > 1 can be written as a product of primes by using inductive reasoning. Let n = 2. Since 2 is prime, n is a product of primes. Suppose n > 2, and the above proposition is true for N < n. If n is prime, then n is a product of primes. If n is composite, then n = ab, where a < n and b < n. Therefore, a and b are products of primes. Hence, n = ab is also a product of primes. Since that has been established, we can now prove that such a product is unique (except for order). Suppose n = p sub1 * p sub2 * ... * p subk = q sub1 * q sub2 * ... * q subr, where the p's and q's are primes. If so, then p sub1 is divisible by (q sub1 * ... * q subr) by Euclid's first theorem. What is the relationship between p sub1 and one of the q's? If the r in q subr equals 1, then p sub1 = q sub1 since the only divisors of q are + or - 1 and + or - q and p > 1, making p = q. What about the other factors in the divisor? If p does not divide q, then the greatest common denominator of p and q is 1 since the only divisors of p are + or - 1 and + or - p. Thus there are integers m and n so that 1 = am + bn. Multiplying by q subr yieds q subr = amq subr + bnq subr. Since we are saying that p is divisible by q, let's say the q sub1 * q subr = cp. Then q subr = amq subr + bnq subr = amq subr + bcm = m(aq subr + bc). Therefore, p is divisible by q sub1 of q sub2 * ... * q subr. If p sub1 is divisible by q sub1, then p sub1 = q sub 1. If this does not work the first time, then repeat the argument until you find an equality. Therefore, one of the p's must equal one of the q's. In any case, rearrange the q's so that p sub1 = q sub1, then p sub1 * p sub2 * ... * p subk= p sub1 * q sub2 * ... * q subr and p sub2 * ... * p subk = q sub2 * ... * q subr, and so on. By the same argument, we can rearrange the remaining q's so that p sub2 = q sub2. Thus n can be expressed uniquely as a product of primes regardless of order, making the fundamental theorem of arithmetic true.

by some punk kid September 6, 2005

Arpita

The first love of a boy 👦 girl having a cute dimple and its look like 👏😮👏😮👏😮 wowwwwww.....

Try to get back in life of arpita!!!!

by Unknown lover 19 November 23, 2021