(x+y)^{n}=\sum _{k=0}^{n}{n \choose k}x^{n-k}y^{k}=\sum _{k=0}^{n}{n \choose k}x^{k}y^{n-k}.

Some good meth for yo head doode.

Person 1: "Yo, do you know that 2*2 =4 and 2+2= 4."
Person 2: "(x+y)^{n}=\sum _{k=0}^{n}{n \choose k}x^{n-k}y^{k}=\sum _{k=0}^{n}{n \choose k}x^{k}y^{n-k}."

by Lurlei139See December 4, 2018

s h 0 0 k

kobain and calum. can also be called: "cabain" or "poison ivy and harley quinn"

bITCH WE BOTH WANT TO DIE ? I'M SO s h 0 0 k

by kobaincut July 27, 2017

k<0

k dominants 0

k is bigger than 0 so it dominants it (k<0)

by blumiblub March 15, 2023