Quod Restaurant & Bar was conceived by Jeremy Mogford and Gary Strivens and opened in Oxford in November 1999, London in August 2001 and in Brighton April 2003. Jeremy Mogford, who founded the Browns Group of Restaurants in 1973, also owns the Old Parsonage Hotel, the Old Bank Hotel and Gee’s Restaurant, all in Oxford.
Quod is an exciting new concept, open all day serving modern Italian inspired food. The menu offers a good selection of fresh fish, chargrilled meats, salads, pastas, pizzas and risottos. The restaurants have a relaxed, informal bar serving coffee, tea, cocktails and an extensive selection of wines by the glass.
Quod is an exciting new concept, open all day serving modern Italian inspired food. The menu offers a good selection of fresh fish, chargrilled meats, salads, pastas, pizzas and risottos. The restaurants have a relaxed, informal bar serving coffee, tea, cocktails and an extensive selection of wines by the glass.
"Quod is one of those places you go to that make you feel like a grown up......Buzzy, bright and bloody brill". Quod Brighton - Itchy Guide 2004
“A throbbing, thriving monument to stylish new eating: another big hit with discerning diners”.
Virgin Hotline
“A throbbing, thriving monument to stylish new eating: another big hit with discerning diners”.
Virgin Hotline
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Queen of the darkness
Otherwise known as ...
Empress of shadows
Temptress of the void
Monarch of the Maelstrom
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Empress of shadows
Temptress of the void
Monarch of the Maelstrom
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Get the quod mug.Originating from the Greek analogous hóper édei deîxai (ὅπερ ἔδει δεῖξαι), meaning "which had to be demonstrated". The phrase is traditionally placed in its abbreviated form (Q.E.D.) at the end of a mathematical proof or philosophical argument. Phrase synonymous with "Quite Easily Done."
∫|Ψ(x, t)|² dx (from -infinity to infinity)= e^(2Γt/ħ) ∫|ψ|²dx(from -infinity to infinity)
The second term is independant of t, therefore Γ=0 & ∫|Ψ(x, t)|² dx (from -infinity to infinity)=∫|ψ|²dx(from -infinity to infinity)=1 {Normalized}
Q.E.D. "quod erat demonstrandum"
The second term is independant of t, therefore Γ=0 & ∫|Ψ(x, t)|² dx (from -infinity to infinity)=∫|ψ|²dx(from -infinity to infinity)=1 {Normalized}
Q.E.D. "quod erat demonstrandum"
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