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fookeling

fuck... but funnier...
FOOKELING. it can be used in similar ways
as fuck. it is a replecement slang term
used amoungst nerds.
what the fookel?.
jessica. you fookeling betch.
i fookeling hate gavin.
i saw gavin fookeling with tom.
tom was fookeling with gavin over fookeling
gay fookeling porn.
by lindsey dddddd May 19, 2008
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Foneface

The expressionless, distracted face a person makes when staring at the screen of his/ her smart phone for long periods of time
He had a real foneface while he was supposed to be listening to the Professor's lecture
by Cloud Computing September 2, 2017
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Related Words

foodementary

The description of food when the culinary expectation is very high, but the result is average.
I went to Tetsuyas and the third dish was foodementary.
by Jeremygoose October 24, 2020
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Fookers

Fooker, Fookers, Fookered

1. Bike pedals from Amazon. Knock offs of RaceFace Chester mountain bike pedals.

2. A way of saying you failed something in mountain biking terms
“Time to shred with my new Fookers”

Aww man I really fookered that jump”
by Fookerman5808 May 23, 2018
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Foofe

The very elusive 3 utensil combo. Similar to a spork, but including the last of the eating utensil triad (knife). Foofe is derived from Fork, spOOn, and kniFE combined to form the pinnacle of eating technology.
Guy 1: Man, I wish there was a utensil to eat without using both of my hands. That way, I could eat and scratch ma' balls at the same time.

Guy 2: There is, it's called a "foofe" you dumbass
by ManBearPig97531 November 4, 2010
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foodness

Why werent you there?
...Foodness.
by Anonymous May 28, 2003
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foode

A first order ordinary differential equation - that is, an equation that relates a function of one variable and it's first derivative in some way.
"Why Elwood, how do I find the solution to dy/dx = y/x?"

"Well that's a simple matter, Eleanor, though I know not why a woman such as yourself would have an interest in maths. That is an example of a separable first order ordinary differential equation, or separable FOODE. Rearrange to get (1/y)dy = (1/x)dx, and integrate both sides to get lny = lnx + c. You may then solve for y, yielding y = xexp(c), where c is an arbitrary constant of integration. Noting exp(c) is itself an arbitrary constant, you may simplify to y = kx. So dy/dx in that differential equation is the derivative of any straight line that passes through the origin."

"Gadzooks! It is far more elementary than I at first had imagined. Now let us get in this motor coach and ride blissfully towards the sunset."
by Ancestral January 8, 2010
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