Two people holding a full size twinkie in their mouth and then engaging in a passionate kiss lasting greater than 5 minutes without swallowing.
Lincoln: "Raoul had to cancel his date with Shantaya because last night Lateefa severed half of his left testicle with a pair of pruning shears while they were cream caking."
Washington: "DAMN"
Washington: "DAMN"
by testicle crusher April 13, 2014
Get the cream caking mug.by .K+. January 10, 2009
Get the fly off the chain mug.Related Words
chaking
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by Countyeasy June 5, 2017
Get the cut the chain mug.In calculus, the chain rule is used to differentiate compositions of functions. It states that for any function f which is dependent on a variable u, and u is a function of a second variable x, then f is a function of x.
In Set Theory:
f(u)=u V u(x)=x V Vf(x)
In Calculus:
df/dx = du/dx(dx/du)
In Set Theory:
f(u)=u V u(x)=x V Vf(x)
In Calculus:
df/dx = du/dx(dx/du)
to differentiate (x+1)^2, one could multiply this out and apply the sum rule (derivative of a sum is the sum of the derivatives); but what if it were (x+1)^55? Suddenly the multipling out doesn't look so nice. To apply the chain rule, we must first define the functions. Let f(x)=(x+1)^55 and u=(x+1). Therefore f(x)=u^55. By the chain rule:
df/dx = df/du(du/dx)
df/dx = d/du(u^55)(du/dx)
df/dx = 55u(du/dx)
We earlier defined the variable "u" as (x+1). Now we substitute this in.
df/dx = 55(x+1)d/dx(x+1)
df/dx = 55x+55(1)
df/dx = 55x+55
df/dx = df/du(du/dx)
df/dx = d/du(u^55)(du/dx)
df/dx = 55u(du/dx)
We earlier defined the variable "u" as (x+1). Now we substitute this in.
df/dx = 55(x+1)d/dx(x+1)
df/dx = 55x+55(1)
df/dx = 55x+55
by Gladwarez July 10, 2006
Get the chain rule mug.by The cake eater August 20, 2010
Get the cakin' mug.one of the sexiest girls i've EVER seen! now im not particularly into gothic girls but this chick is FINE! all guys go to www.chainsawsally.org to find out what i mean...OMFG! SHE IS HOT! I CANT SAY IT ENUFF!
by David Towle June 5, 2004
Get the chainsaw sally mug.Are you on the phone with him/her? Damn, you still cakin'!
Friend 1: Where is Friend 2?
Friend 3: At the house cakin'.
Friend 1: Where is Friend 2?
Friend 3: At the house cakin'.
by unorabbit May 4, 2006
Get the Cakin' mug.