its a way of writing the number "127'
these arent random
some of you might notice a pattern
1+1 is 2 so you do
1+1+2 which is 4
1+1+2+4 = 8
1+1+2+4+8 + 16
when you get to 16 break it down to single digit and add them seperately so
1+1+2+4+"1+6"
you will get 23 so
1 + 1 + 2 + 4 + 8 + 1 + 6 + "2 + 3"
repeat
i suck at explaining things
these arent random
some of you might notice a pattern
1+1 is 2 so you do
1+1+2 which is 4
1+1+2+4 = 8
1+1+2+4+8 + 16
when you get to 16 break it down to single digit and add them seperately so
1+1+2+4+"1+6"
you will get 23 so
1 + 1 + 2 + 4 + 8 + 1 + 6 + "2 + 3"
repeat
i suck at explaining things
did you know 1+1+2+4+8+1+6+2+3+2+8+3+8+4+9+6+2+7+0+7+7+9+1+1+0+1+1+3+1+7+1+1+5+1+2+2 is a way of writing 127
by cosmnik June 07, 2021
Don't try solving it, just put it into google, it makes a nice heart!
idea from some other guy
thanks
idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5
by giant salamanders eat pant May 15, 2020
Don't try to solve it, LOL .
Paste it on Google and a Heart symbol will appear <3
It's a graph drawing from that expression .
Paste it on Google and a Heart symbol will appear <3
It's a graph drawing from that expression .
Hey babe. (sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 !!!
by Nguyen Vu Long December 06, 2011
On May 15, 2020, a user known as "giant salamanders eat paint" said, "Don't try solving it, just put it into google, it makes a nice heart!
idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5" Now this guy forgot to credit the original user who made this. Me. And some dude from 2011 named "Nguyen Vu Long". SO CREDIT US!
idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5" Now this guy forgot to credit the original user who made this. Me. And some dude from 2011 named "Nguyen Vu Long". SO CREDIT US!
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5
Copy-paste it noobs.
Copy-paste it noobs.
by WrySquirrel3069 May 29, 2020
This was defined in 2011, and the user who defined it said to copy-paste it and something will happen...
(sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 is a line of code that can be pasted into google and stuff happens.Copy-paste this: (sqrt(cos(x))*cos(200 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5
by WrySquirrel3069 May 12, 2020
by Papa günter January 07, 2018
The equation (a+b)² = a² + 2ab + b² is an example of the formula for squaring a binomial. When you expand (a+b)², it means you are multiplying (a+b) by itself.
To expand (a+b)², you can use the distributive property of multiplication over addition. This means you multiply each term in the first expression by each term in the second expression and then add the results.
So, when you expand (a+b)², you get:
(a+b)² = (a+b)(a+b) = a(a+b) + b(a+b) = a² + ab + ab + b² = a² + 2ab + b²
To expand (a+b)², you can use the distributive property of multiplication over addition. This means you multiply each term in the first expression by each term in the second expression and then add the results.
So, when you expand (a+b)², you get:
(a+b)² = (a+b)(a+b) = a(a+b) + b(a+b) = a² + ab + ab + b² = a² + 2ab + b²
Bro- sup dude
Me- (a+b)^2=a^2+2ab+b^2
Me- (a+b)^2=a^2+2ab+b^2
by Fuck me:) April 02, 2024