Same theory as Schroeder's Cat, if you're blindfolded and fisting. You do not know whether you are fisting a vagina or a rectum until you remove the blindfold.
Have you heard of Schroedinger's Cat?
No, but have you ever heard of Quantum Fisting? Great time at my stag party.... I think.
No, but have you ever heard of Quantum Fisting? Great time at my stag party.... I think.
by Quantosexual December 08, 2018
A pimp that resides in another realm of reality.
A man that has mastered the flow of the universe, living in balance and accordance with his own nature to such a degree that nothing can faze him any longer, especially women.
Can drop panties without lifting a single finger & control the female psyche just by existing in a woman's vicinity.
A man that has mastered the flow of the universe, living in balance and accordance with his own nature to such a degree that nothing can faze him any longer, especially women.
Can drop panties without lifting a single finger & control the female psyche just by existing in a woman's vicinity.
Guy 1: Do you see that guy over there surrounded by women?
Guy 2: Yes, is he rich, famous?
Guy 1: No. They call him the Quantum Rizzicist. He truly is a master of Rizz at an atomic level.
Guy 2: Yes, is he rich, famous?
Guy 1: No. They call him the Quantum Rizzicist. He truly is a master of Rizz at an atomic level.
by TheKid456 May 01, 2023
iℏ⋅(∂Ψ(x,t))/(∂t)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)
(This is how the average conversation about quantum mechanics generally goes:)
Person 1: Omg like literally iℏ⋅(∂Ψ(x,t))/(∂t)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)
Person 2: Right! Lmao it's just ∂Ψ(x,t)=Ae^(i(kx-ωt))
Person 1: Exactly! And iℏ⋅(∂Ψ(x,t))/(∂t)=iℏ⋅(∂Ae^(i(kx-ωt)))/(∂t)=ℏωAe^(i(kx-ωt))
Person 2: Hahaha! -ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)=-ℏ^2/2m⋅(∂^2Ae^(i(kx-ωt)))/(∂x^2)
Person 1: Yeah and it's like -(ikℏ^2)/2m⋅(∂Ae^(i(kx-ωt)))/(∂x)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)=-ℏ^2/2m⋅(∂^2Ae^(i(kx-ωt)))/(∂x^2)
Person 2: Bro I was thinking the same thing, as soon as she walked in my mind just went (ℏ^2⋅k^2)/2m⋅Ae^(i(kx-ωt))= -(ikℏ^2)/2m⋅(∂Ae^(i(kx-ωt)))/(∂x)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)=-ℏ^2/2m⋅(∂^2Ae^(i(kx-ωt)))/(∂x^2)
Person 1: Pfffftttt!!! (ℏ^2⋅k^2)/2m=ℏω
Person 2: Lol yeah man, great shit right there... So anyway, how's Jack?
Person 1: Omg like literally iℏ⋅(∂Ψ(x,t))/(∂t)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)
Person 2: Right! Lmao it's just ∂Ψ(x,t)=Ae^(i(kx-ωt))
Person 1: Exactly! And iℏ⋅(∂Ψ(x,t))/(∂t)=iℏ⋅(∂Ae^(i(kx-ωt)))/(∂t)=ℏωAe^(i(kx-ωt))
Person 2: Hahaha! -ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)=-ℏ^2/2m⋅(∂^2Ae^(i(kx-ωt)))/(∂x^2)
Person 1: Yeah and it's like -(ikℏ^2)/2m⋅(∂Ae^(i(kx-ωt)))/(∂x)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)=-ℏ^2/2m⋅(∂^2Ae^(i(kx-ωt)))/(∂x^2)
Person 2: Bro I was thinking the same thing, as soon as she walked in my mind just went (ℏ^2⋅k^2)/2m⋅Ae^(i(kx-ωt))= -(ikℏ^2)/2m⋅(∂Ae^(i(kx-ωt)))/(∂x)=-ℏ^2/2m⋅(∂^2Ψ(x,t))/(∂x^2)=-ℏ^2/2m⋅(∂^2Ae^(i(kx-ωt)))/(∂x^2)
Person 1: Pfffftttt!!! (ℏ^2⋅k^2)/2m=ℏω
Person 2: Lol yeah man, great shit right there... So anyway, how's Jack?
by wugugugug May 06, 2021
by Call_8304765664 December 13, 2019
These two words are used to describe something very desirable (whether it be a food, an object, etc.) that is just out of reach.
by Dayna_Rules October 28, 2009
by Davingi March 28, 2018
A joke relating to Quantum Physics and the concept of a joke about Quantum Physics that repeats every cycle of the joke in a loop. The joke itself can be found inside the popular game, Undertale.
So I opened the Quantum Physics book and there, unbelievably, I found another book. This book, however, was a joke book about Quantum Jokes. After flipping that book open I swear to you, there was yet another Quantum Physics book. I don't even know how the books got in each other in the first place. That whole situation turned out to be a real mindfuck.
by Nihils June 14, 2020