99999999 

SomethIng that can be used in a robux and or v bucks scam link or video

Person in the video: this is how you get 99999999 robux
Little Timmy: oh boy time to get free robux
Little Timmy: *get scam and leaked his location*
Person in the video: open da noor

99999999 by Chad pvz2 fan November 13, 2023

does 9.99999999 = 10? 

like if you think it is and dislike if you think it is not

does 9.99999999 = 10?

does 9.99999999 = 10? by URB4N D1C710N4RY April 12, 2021

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

Don't try solving it, just put it into google, it makes a nice heart!

idea from some other guy
thanks

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 by giant salamanders eat pant May 15, 2020

999999999888888887777777666666555554444333221

When you've tried each combination of letters possible, so you decide to go through every number combination possible.

Usually when bored during work and or school

Guy 1 : instead of being productive, why not put in 999999999888888887777777666666555554444333221 into the google search bar?

Guy 2 : good idea, good idea.

999999999888888887777777666666555554444333221 by blocksterr January 22, 2019

9999999999999999999999 

too manny 9s too mannnnnnnnnnnnyyyyyyyyyy

your iq is (not) 9999999999999999999999

9999999999999999999999 by de retard January 25, 2021

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

On May 15, 2020, a user known as "giant salamanders eat paint" said, "Don't try solving it, just put it into google, it makes a nice heart!

idea from some other guy
thanks
(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5" Now this guy forgot to credit the original user who made this. Me. And some dude from 2011 named "Nguyen Vu Long". SO CREDIT US!

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5

Copy-paste it noobs.

(sqrt(cos(x))*cos(999999999999999999999999999999999999999999999999999 x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01, sqrt(9-x^2), -sqrt(9-x^2) from -4.5 to 4.5 by WrySquirrel3069 May 29, 2020

.999999999~ 

Grrrrrrr you anger me....learn some maths! .9999 recurring IS equal to 1! Hell, I'll even prove it for you if you like -
We all know that 1/3 (a third) can be written decimally as 0.333333 recurring (i.e. the 3s go on forever). It is also obvious that by multiplying a third by three, we get three thirds (3/3) , which is equal to one.
-
If we look at this same process decimally, take the number 0.33333 recurring and multiply it by 3, and you will see that each 3 in the sequence gets turned into a 9. This gives us .99999 recurring, which, since it is the same as 3/3, is also equal to 1, as explained in the previous paragraph.
-
The reason for this is that as you add more 9s onto the number 0.9 (after the decimal point), it gets closer and closer to 1. Since there are an infinite number of 9s after the point in 0.99999 recurring, the difference between this number and 1 must be infinitely small, and therefore cannot be any greater than 0.
QED.

.999999999~ (recurring) is equal to one because it is .333333~ (1/3) multiplied by 3.

.999999999~ by katzell September 25, 2005