Definitions by Ivy Leigh
Pneuminominator
In the fraction:
(a/b)/c
-where "a" is the Neumerator and "c" is the Denominator, then "b" is the Pneumonominator
(a/b)/c
-where "a" is the Neumerator and "c" is the Denominator, then "b" is the Pneumonominator
To find the answer to (1/2)/4 you need to multiply the Pneuminominator (2) by the Denominator (4) to get the answer- 1/8
(The "P" is silent)
(The "P" is silent)
Pneuminominator by Ivy Leigh May 25, 2006
Pneuminominator
In the fraction:
(a/b)/c
-where "a" is the Neumerator and "c" is the Denominator, then "b" is the Pneumonominator
(a/b)/c
-where "a" is the Neumerator and "c" is the Denominator, then "b" is the Pneumonominator
To find the answer to (1/2)/4 you need to multiply the Pneuminominator (2) by the Denominator (4) to get the answer- 1/8
(The "P" is silent)
(The "P" is silent)
Pneuminominator by Ivy Leigh May 25, 2006