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The Rolling Theorum is an equation used in current day mathematics. It can be used to find out a large amount of information about geometry when reduced properly (cylinders, specifically, hence the name "Rolling Theorum.")

This equation must be solved for y where x = Z||R and is as follows:

y = ((R²I²CK)/RI) + (2X)/((BA)(R²)(EL))

so, we have to start by dividing the left side of the plus sign. Which leaves us with..

y = (RICK) + (2X)/((BA)(R²)(EL))

Next, we come to the R², which is (RR)

y = (RICK) + (2X)/((BA)(RR)(EL))

And to make it easier to read, we'll leave it as R²

y = (RICK) + (2X)/(BAR²EL)

Now we come to the 2X. We said earlier that it was equal to Z || R, which means Z or R. So let's plug this in..

y = (RICK) + (2(Z || R))/(BAR²EL)

Now, any StarFox fan will recognize this as a Barrel Roll, as 2 times Z or R is a Barrel Roll.

y = (RICK) + (BARREL ROLL)/(BAR²EL)

Simplify BARREL..

y = (RICK) + (BAR²EL ROLL)/(BAR²EL)

divide what's on the right side of the plus sign..

y = RICK + ROLL

AND THERE YOU HAVE IT. Y = RICK ROLL. AND THIS IS TRUELY WHY IT IS CALLED THE ROLLING THEORUM.

This equation must be solved for y where x = Z||R and is as follows:

y = ((R²I²CK)/RI) + (2X)/((BA)(R²)(EL))

so, we have to start by dividing the left side of the plus sign. Which leaves us with..

y = (RICK) + (2X)/((BA)(R²)(EL))

Next, we come to the R², which is (RR)

y = (RICK) + (2X)/((BA)(RR)(EL))

And to make it easier to read, we'll leave it as R²

y = (RICK) + (2X)/(BAR²EL)

Now we come to the 2X. We said earlier that it was equal to Z || R, which means Z or R. So let's plug this in..

y = (RICK) + (2(Z || R))/(BAR²EL)

Now, any StarFox fan will recognize this as a Barrel Roll, as 2 times Z or R is a Barrel Roll.

y = (RICK) + (BARREL ROLL)/(BAR²EL)

Simplify BARREL..

y = (RICK) + (BAR²EL ROLL)/(BAR²EL)

divide what's on the right side of the plus sign..

y = RICK + ROLL

AND THERE YOU HAVE IT. Y = RICK ROLL. AND THIS IS TRUELY WHY IT IS CALLED THE ROLLING THEORUM.

"DAMNIT DUDE, I got Rick Roll'd from The Rolling Theorum today!"

"I can use the Rolling Theorum to determine the Length of this Cylinder"

"I can use the Rolling Theorum to determine the Length of this Cylinder"

by Anonymous - 0GM
January 03, 2008