| 2. | 1 = 2 | ||
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1. x = y
2. xy = y^2 3. xy - x^2 = y^2 - x^2 4. x(y - x) = (y + x)(y - x) 5. x = y + x 6. x = x + x 7. x = 2x 8. 1 = 2 QED As proven, 1 = 2, thus 0 = 1, etc. And so for any number i, there is an equivalent j that is not equal to i.
This is further explained in the Identity Theft Theorem. |
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| 1. | 1 = 2 | ||
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The person before made a mistake in their proof.
1. x = y 2. xy = y^2 3. xy - x^2 = y^2 - x^2 4. x(y - x) = (y + x)(y - x) So far so good. 4.5. x = (y + x)(y - x)/(y - x)] is what they did to get to step 5, which says: 5. x = y + x This is wrong though. since x = y, y -x = 0, and so you can't divide by y - x. Anyone who says 1 = 2 is wrong.
1 != 2 |
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